Base | Representation |
---|---|
bin | 10000011101100001011… |
… | …100011001100000110011 |
3 | 11000010212001111200212121 |
4 | 100131201130121200303 |
5 | 122013210033431311 |
6 | 2223400554335111 |
7 | 144504316555624 |
oct | 20354134314063 |
9 | 4003761450777 |
10 | 1131211233331 |
11 | 3a6820283603 |
12 | 1632a042a497 |
13 | 8289909888a |
14 | 3ca72727a4b |
15 | 1e65aad3b71 |
hex | 10761719833 |
1131211233331 has 2 divisors, whose sum is σ = 1131211233332. Its totient is φ = 1131211233330.
The previous prime is 1131211233293. The next prime is 1131211233337. The reversal of 1131211233331 is 1333321121311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131211233331 - 219 = 1131210709043 is a prime.
It is a super-2 number, since 2×11312112333312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131211233296 and 1131211233305.
It is not a weakly prime, because it can be changed into another prime (1131211233337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565605616665 + 565605616666.
It is an arithmetic number, because the mean of its divisors is an integer number (565605616666).
Almost surely, 21131211233331 is an apocalyptic number.
1131211233331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131211233331 is an equidigital number, since it uses as much as digits as its factorization.
1131211233331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 972, while the sum is 25.
Adding to 1131211233331 its reverse (1333321121311), we get a palindrome (2464532354642).
The spelling of 1131211233331 in words is "one trillion, one hundred thirty-one billion, two hundred eleven million, two hundred thirty-three thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •