11312124322133 has 2 divisors, whose sum is σ = 11312124322134. Its totient is φ = 11312124322132.

The previous prime is 11312124322117. The next prime is 11312124322151. The reversal of 11312124322133 is 33122342121311.

11312124322133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8537108079889 + 2775016242244 = 2921833^2 + 1665838^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312124322133 - 2⁴ = 11312124322117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11312124322096 and 11312124322105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312124324133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656062161066 + 5656062161067.

It is an arithmetic number, because the mean of its divisors is an integer number (5656062161067).

Almost surely, 2^{11312124322133} is an apocalyptic number.

It is an amenable number.

11312124322133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312124322133 is an equidigital number, since it uses as much as digits as its factorization.

11312124322133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 29.

Adding to 11312124322133 its reverse (33122342121311), we get a palindrome (44434466443444).

The spelling of 11312124322133 in words is "eleven trillion, three hundred twelve billion, one hundred twenty-four million, three hundred twenty-two thousand, one hundred thirty-three".