1131214093 has 2 divisors, whose sum is σ = 1131214094. Its totient is φ = 1131214092.

The previous prime is 1131214081. The next prime is 1131214111. The reversal of 1131214093 is 3904121311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1092500809 + 38713284 = 33053^2 + 6222^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131214093 - 2¹⁷ = 1131083021 is a prime.

It is a super-3 number, since 3×1131214093³ (a number of 28 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131214003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565607046 + 565607047.

It is an arithmetic number, because the mean of its divisors is an integer number (565607047).

Almost surely, 2^1131214093 is an apocalyptic number.

It is an amenable number.

1131214093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131214093 is an equidigital number, since it uses as much as digits as its factorization.

1131214093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 1131214093 is about 33633.5263241903. The cubic root of 1131214093 is about 1041.9533349153.

The spelling of 1131214093 in words is "one billion, one hundred thirty-one million, two hundred fourteen thousand, ninety-three".