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1131222021253 is a prime number
BaseRepresentation
bin10000011101100010000…
…101100011010010000101
311000010212210210210010021
4100131202011203102011
5122013220314140003
62223402021455141
7144504510346402
oct20354205432205
94003783723107
101131222021253
113a6826381745
121632a3b714b1
138289b3a4c6c
143ca73d352a9
151e65ba152bd
hex10762163485

1131222021253 has 2 divisors, whose sum is σ = 1131222021254. Its totient is φ = 1131222021252.

The previous prime is 1131222021247. The next prime is 1131222021323. The reversal of 1131222021253 is 3521202221311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1111586445124 + 19635576129 = 1054318^2 + 140127^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131222021253 is a prime.

It is a super-2 number, since 2×11312220212532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131222021203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565611010626 + 565611010627.

It is an arithmetic number, because the mean of its divisors is an integer number (565611010627).

Almost surely, 21131222021253 is an apocalyptic number.

It is an amenable number.

1131222021253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131222021253 is an equidigital number, since it uses as much as digits as its factorization.

1131222021253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1131222021253 its reverse (3521202221311), we get a palindrome (4652424242564).

The spelling of 1131222021253 in words is "one trillion, one hundred thirty-one billion, two hundred twenty-two million, twenty-one thousand, two hundred fifty-three".