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113122422173 is a prime number
BaseRepresentation
bin110100101011010011…
…1110010110110011101
3101210222200210110100202
41221112213302312131
53323133320002143
6123545010033245
711113164503045
oct1512647626635
9353880713322
10113122422173
1143a7a727102
1219b10578825
13a88a3759a7
145691b76725
152e212beab8
hex1a569f2d9d

113122422173 has 2 divisors, whose sum is σ = 113122422174. Its totient is φ = 113122422172.

The previous prime is 113122422137. The next prime is 113122422197. The reversal of 113122422173 is 371224221311.

It is a happy number.

Together with previous prime (113122422137) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105272993764 + 7849428409 = 324458^2 + 88597^2 .

It is a cyclic number.

It is not a de Polignac number, because 113122422173 - 28 = 113122421917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113122422103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561211086 + 56561211087.

It is an arithmetic number, because the mean of its divisors is an integer number (56561211087).

Almost surely, 2113122422173 is an apocalyptic number.

It is an amenable number.

113122422173 is a deficient number, since it is larger than the sum of its proper divisors (1).

113122422173 is an equidigital number, since it uses as much as digits as its factorization.

113122422173 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4032, while the sum is 29.

Adding to 113122422173 its reverse (371224221311), we get a palindrome (484346643484).

The spelling of 113122422173 in words is "one hundred thirteen billion, one hundred twenty-two million, four hundred twenty-two thousand, one hundred seventy-three".