Search a number
-
+
113123101631 is a prime number
BaseRepresentation
bin110100101011010101…
…0011000101110111111
3101210222202001222101212
41221112222120232333
53323134003223011
6123545032355035
711113203333011
oct1512652305677
9353882058355
10113123101631
1143a80050641
1219b10845a7b
13a88a553037
145691cb21b1
152e213a608b
hex1a56a98bbf

113123101631 has 2 divisors, whose sum is σ = 113123101632. Its totient is φ = 113123101630.

The previous prime is 113123101621. The next prime is 113123101633. The reversal of 113123101631 is 136101321311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113123101631 is a prime.

It is a super-2 number, since 2×1131231016312 (a number of 23 digits) contains 22 as substring.

Together with 113123101633, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113123101597 and 113123101606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113123101633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561550815 + 56561550816.

It is an arithmetic number, because the mean of its divisors is an integer number (56561550816).

Almost surely, 2113123101631 is an apocalyptic number.

113123101631 is a deficient number, since it is larger than the sum of its proper divisors (1).

113123101631 is an equidigital number, since it uses as much as digits as its factorization.

113123101631 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 113123101631 its reverse (136101321311), we get a palindrome (249224422942).

The spelling of 113123101631 in words is "one hundred thirteen billion, one hundred twenty-three million, one hundred one thousand, six hundred thirty-one".