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113123140020 = 22325111312571697
BaseRepresentation
bin110100101011010101…
…0100010000110110100
3101210222202010221001200
41221112222202012310
53323134010440040
6123545033252500
711113203552642
oct1512652420664
9353882127050
10113123140020
1143a80077470
1219b10864130
13a88a567657
145691cc2192
152e213b2630
hex1a56aa21b4

113123140020 has 288 divisors, whose sum is σ = 378883080576. Its totient is φ = 27092582400.

The previous prime is 113123140007. The next prime is 113123140027. The reversal of 113123140020 is 20041321311.

113123140020 is a `hidden beast` number, since 1 + 1 + 31 + 231 + 400 + 2 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 113123139975 and 113123140002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113123140027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 66659812 + ... + 66661508.

It is an arithmetic number, because the mean of its divisors is an integer number (1315566252).

Almost surely, 2113123140020 is an apocalyptic number.

113123140020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113123140020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (189441540288).

113123140020 is an abundant number, since it is smaller than the sum of its proper divisors (265759940556).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113123140020 is a wasteful number, since it uses less digits than its factorization.

113123140020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2111 (or 2106 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 113123140020 its reverse (20041321311), we get a palindrome (133164461331).

The spelling of 113123140020 in words is "one hundred thirteen billion, one hundred twenty-three million, one hundred forty thousand, twenty".