Base | Representation |
---|---|
bin | 110100101011010101… |
… | …0100010100111010101 |
3 | 101210222202011000220202 |
4 | 1221112222202213111 |
5 | 3323134011021401 |
6 | 123545033310245 |
7 | 11113203562004 |
oct | 1512652424725 |
9 | 353882130822 |
10 | 113123142101 |
11 | 43a80078a92 |
12 | 19b10865385 |
13 | a88a568598 |
14 | 5691cc2c3b |
15 | 2e213b306b |
hex | 1a56aa29d5 |
113123142101 has 2 divisors, whose sum is σ = 113123142102. Its totient is φ = 113123142100.
The previous prime is 113123142049. The next prime is 113123142133. The reversal of 113123142101 is 101241321311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 57710452900 + 55412689201 = 240230^2 + 235399^2 .
It is a cyclic number.
It is not a de Polignac number, because 113123142101 - 230 = 112049400277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113123142151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561571050 + 56561571051.
It is an arithmetic number, because the mean of its divisors is an integer number (56561571051).
Almost surely, 2113123142101 is an apocalyptic number.
It is an amenable number.
113123142101 is a deficient number, since it is larger than the sum of its proper divisors (1).
113123142101 is an equidigital number, since it uses as much as digits as its factorization.
113123142101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 113123142101 its reverse (101241321311), we get a palindrome (214364463412).
The spelling of 113123142101 in words is "one hundred thirteen billion, one hundred twenty-three million, one hundred forty-two thousand, one hundred one".
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