Base | Representation |
---|---|
bin | 10101000100100010… |
… | …11011101000011101 |
3 | 1002012101022010121011 |
4 | 22202101123220131 |
5 | 141131434210323 |
6 | 5110304135221 |
7 | 550221632353 |
oct | 124221335035 |
9 | 32171263534 |
10 | 11312413213 |
11 | 4885620532 |
12 | 2238607511 |
13 | 10b388053a |
14 | 7945957d3 |
15 | 46320120d |
hex | 2a245ba1d |
11312413213 has 2 divisors, whose sum is σ = 11312413214. Its totient is φ = 11312413212.
The previous prime is 11312413157. The next prime is 11312413237. The reversal of 11312413213 is 31231421311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9867044889 + 1445368324 = 99333^2 + 38018^2 .
It is an emirp because it is prime and its reverse (31231421311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11312413213 - 29 = 11312412701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312413283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656206606 + 5656206607.
It is an arithmetic number, because the mean of its divisors is an integer number (5656206607).
Almost surely, 211312413213 is an apocalyptic number.
It is an amenable number.
11312413213 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312413213 is an equidigital number, since it uses as much as digits as its factorization.
11312413213 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432, while the sum is 22.
Adding to 11312413213 its reverse (31231421311), we get a palindrome (42543834524).
The spelling of 11312413213 in words is "eleven billion, three hundred twelve million, four hundred thirteen thousand, two hundred thirteen".
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