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113124202421311 is a prime number
BaseRepresentation
bin11001101110001011000111…
…111001101001110000111111
3112211112120100011120210100101
4121232023013321221300333
5104311411331304440221
61040332312520141531
732553645123113344
oct3156130771516077
9484476304523311
10113124202421311
1133054783141354
121083028a6078a7
134b17749831543
141dd13523467cb
15d12947d18d91
hex66e2c7e69c3f

113124202421311 has 2 divisors, whose sum is σ = 113124202421312. Its totient is φ = 113124202421310.

The previous prime is 113124202421309. The next prime is 113124202421317.

113124202421311 is nontrivially palindromic in base 10.

It is a weak prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 113124202421311 - 21 = 113124202421309 is a prime.

Together with 113124202421309, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 113124202421311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113124202421317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56562101210655 + 56562101210656.

It is an arithmetic number, because the mean of its divisors is an integer number (56562101210656).

Almost surely, 2113124202421311 is an apocalyptic number.

113124202421311 is a deficient number, since it is larger than the sum of its proper divisors (1).

113124202421311 is an equidigital number, since it uses as much as digits as its factorization.

113124202421311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 28.

It can be divided in two parts, 11312420 and 2421311, that added together give a palindrome (13733731).

The spelling of 113124202421311 in words is "one hundred thirteen trillion, one hundred twenty-four billion, two hundred two million, four hundred twenty-one thousand, three hundred eleven".