11312433400 has 48 divisors (see below), whose sum is σ = 26439200640. Its totient is φ = 4501267200.

The previous prime is 11312433397. The next prime is 11312433409. The reversal of 11312433400 is 433421311.

It is a super-2 number, since 2×11312433400² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312433409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 109869 + ... + 186268.

It is an arithmetic number, because the mean of its divisors is an integer number (550816680).

Almost surely, 2^11312433400 is an apocalyptic number.

11312433400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11312433400 is an abundant number, since it is smaller than the sum of its proper divisors (15126767240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11312433400 is a wasteful number, since it uses less digits than its factorization.

11312433400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 296344 (or 296335 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 11312433400 its reverse (433421311), we get a palindrome (11745854711).

The spelling of 11312433400 in words is "eleven billion, three hundred twelve million, four hundred thirty-three thousand, four hundred".