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11312551254049 is a prime number
BaseRepresentation
bin1010010010011110100010…
…0110010101100000100001
31111001110200010222110210121
42210213220212111200201
52440321101110112144
640020525253400241
72245206365046253
oct244475046254041
944043603873717
1011312551254049
1136716982a1141
121328546639081
136409cc6766b6
142b175d5cdcd3
151493eabc8384
hexa49e8995821

11312551254049 has 2 divisors, whose sum is σ = 11312551254050. Its totient is φ = 11312551254048.

The previous prime is 11312551254047. The next prime is 11312551254133. The reversal of 11312551254049 is 94045215521311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11056575970449 + 255975283600 = 3325143^2 + 505940^2 .

It is an emirp because it is prime and its reverse (94045215521311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11312551254049 - 21 = 11312551254047 is a prime.

Together with 11312551254047, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11312551253996 and 11312551254014.

It is not a weakly prime, because it can be changed into another prime (11312551254041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656275627024 + 5656275627025.

It is an arithmetic number, because the mean of its divisors is an integer number (5656275627025).

Almost surely, 211312551254049 is an apocalyptic number.

It is an amenable number.

11312551254049 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312551254049 is an equidigital number, since it uses as much as digits as its factorization.

11312551254049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 43.

The spelling of 11312551254049 in words is "eleven trillion, three hundred twelve billion, five hundred fifty-one million, two hundred fifty-four thousand, forty-nine".