11312551254133 has 2 divisors, whose sum is σ = 11312551254134. Its totient is φ = 11312551254132.

The previous prime is 11312551254049. The next prime is 11312551254143. The reversal of 11312551254133 is 33145215521311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7029402295204 + 4283148958929 = 2651302^2 + 2069577^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11312551254133 is a prime.

It is a super-2 number, since 2×11312551254133² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11312551254092 and 11312551254101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312551254143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656275627066 + 5656275627067.

It is an arithmetic number, because the mean of its divisors is an integer number (5656275627067).

Almost surely, 2^{11312551254133} is an apocalyptic number.

It is an amenable number.

11312551254133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312551254133 is an equidigital number, since it uses as much as digits as its factorization.

11312551254133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54000, while the sum is 37.

Adding to 11312551254133 its reverse (33145215521311), we get a palindrome (44457766775444).

The spelling of 11312551254133 in words is "eleven trillion, three hundred twelve billion, five hundred fifty-one million, two hundred fifty-four thousand, one hundred thirty-three".