Base | Representation |
---|---|
bin | 10000011101100110101… |
… | …111011110111100110100 |
3 | 11000011002020202201210002 |
4 | 100131212233132330310 |
5 | 122013400312404140 |
6 | 2223413451450432 |
7 | 144506446243526 |
oct | 20354657367464 |
9 | 4004066681702 |
10 | 1131300122420 |
11 | 3a6866476266 |
12 | 163306156a18 |
13 | 828b161bc80 |
14 | 3ca80465a16 |
15 | 1e6637e1415 |
hex | 10766bdef34 |
1131300122420 has 48 divisors (see below), whose sum is σ = 2584854865488. Its totient is φ = 413404508160.
The previous prime is 1131300122417. The next prime is 1131300122443. The reversal of 1131300122420 is 242210031311.
It can be written as a sum of positive squares in 8 ways, for example, as 28892520484 + 1102407601936 = 169978^2 + 1049956^2 .
It is a super-3 number, since 3×11313001224203 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 1131300122392 and 1131300122401.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22403411 + ... + 22453850.
It is an arithmetic number, because the mean of its divisors is an integer number (53851143031).
Almost surely, 21131300122420 is an apocalyptic number.
1131300122420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1131300122420 is an abundant number, since it is smaller than the sum of its proper divisors (1453554743068).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131300122420 is a wasteful number, since it uses less digits than its factorization.
1131300122420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44857380 (or 44857378 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 1131300122420 its reverse (242210031311), we get a palindrome (1373510153731).
The spelling of 1131300122420 in words is "one trillion, one hundred thirty-one billion, three hundred million, one hundred twenty-two thousand, four hundred twenty".
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