1131300313133 has 2 divisors, whose sum is σ = 1131300313134. Its totient is φ = 1131300313132.

The previous prime is 1131300313127. The next prime is 1131300313181. The reversal of 1131300313133 is 3313130031311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1126141195204 + 5159117929 = 1061198^2 + 71827^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131300313133 - 2¹² = 1131300309037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131300313099 and 1131300313108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131300313123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565650156566 + 565650156567.

It is an arithmetic number, because the mean of its divisors is an integer number (565650156567).

Almost surely, 2^{1131300313133} is an apocalyptic number.

It is an amenable number.

1131300313133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131300313133 is an equidigital number, since it uses as much as digits as its factorization.

1131300313133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 729, while the sum is 23.

Adding to 1131300313133 its reverse (3313130031311), we get a palindrome (4444430344444).

The spelling of 1131300313133 in words is "one trillion, one hundred thirty-one billion, three hundred million, three hundred thirteen thousand, one hundred thirty-three".