1131300313181 has 2 divisors, whose sum is σ = 1131300313182. Its totient is φ = 1131300313180.

The previous prime is 1131300313133. The next prime is 1131300313201. The reversal of 1131300313181 is 1813130031311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 660141625081 + 471158688100 = 812491^2 + 686410^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131300313181 - 2¹⁰ = 1131300312157 is a prime.

It is a super-2 number, since 2×1131300313181² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1131300313181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131300319181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565650156590 + 565650156591.

It is an arithmetic number, because the mean of its divisors is an integer number (565650156591).

Almost surely, 2^{1131300313181} is an apocalyptic number.

It is an amenable number.

1131300313181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131300313181 is an equidigital number, since it uses as much as digits as its factorization.

1131300313181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 26.

Adding to 1131300313181 its reverse (1813130031311), we get a palindrome (2944430344492).

The spelling of 1131300313181 in words is "one trillion, one hundred thirty-one billion, three hundred million, three hundred thirteen thousand, one hundred eighty-one".