11313003133349 has 2 divisors, whose sum is σ = 11313003133350. Its totient is φ = 11313003133348.

The previous prime is 11313003133337. The next prime is 11313003133351. The reversal of 11313003133349 is 94333130031311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9028113921124 + 2284889212225 = 3004682^2 + 1511585^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11313003133349 is a prime.

Together with 11313003133351, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313003133379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656501566674 + 5656501566675.

It is an arithmetic number, because the mean of its divisors is an integer number (5656501566675).

Almost surely, 2^{11313003133349} is an apocalyptic number.

It is an amenable number.

11313003133349 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313003133349 is an equidigital number, since it uses as much as digits as its factorization.

11313003133349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26244, while the sum is 35.

The spelling of 11313003133349 in words is "eleven trillion, three hundred thirteen billion, three million, one hundred thirty-three thousand, three hundred forty-nine".