Base | Representation |
---|---|
bin | 1010010010100000010000… |
… | …0000111010011100111101 |
3 | 1111001111212012110110012011 |
4 | 2210220010000322130331 |
5 | 2440323021332042244 |
6 | 40021043044011221 |
7 | 2245223651425015 |
oct | 244500400723475 |
9 | 44044765413164 |
10 | 11313011205949 |
11 | 3671903994882 |
12 | 1328654690b11 |
13 | 640a73a4909b |
14 | 2b17a471cc45 |
15 | 149426280434 |
hex | a4a0403a73d |
11313011205949 has 2 divisors, whose sum is σ = 11313011205950. Its totient is φ = 11313011205948.
The previous prime is 11313011205883. The next prime is 11313011206027. The reversal of 11313011205949 is 94950211031311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7325780997924 + 3987230208025 = 2706618^2 + 1996805^2 .
It is a cyclic number.
It is not a de Polignac number, because 11313011205949 - 239 = 10763255392061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313011202949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656505602974 + 5656505602975.
It is an arithmetic number, because the mean of its divisors is an integer number (5656505602975).
Almost surely, 211313011205949 is an apocalyptic number.
It is an amenable number.
11313011205949 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313011205949 is an equidigital number, since it uses as much as digits as its factorization.
11313011205949 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 40.
The spelling of 11313011205949 in words is "eleven trillion, three hundred thirteen billion, eleven million, two hundred five thousand, nine hundred forty-nine".
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