11313011320 has 64 divisors (see below), whose sum is σ = 27428375520. Its totient is φ = 4174662144.

The previous prime is 11313011309. The next prime is 11313011323. The reversal of 11313011320 is 2311031311.

11313011320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 11313011294 and 11313011303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313011323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1048674 + ... + 1059406.

Almost surely, 2^11313011320 is an apocalyptic number.

11313011320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11313011320 is an abundant number, since it is smaller than the sum of its proper divisors (16115364200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313011320 is a wasteful number, since it uses less digits than its factorization.

11313011320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12784 (or 12780 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11313011320 its reverse (2311031311), we get a palindrome (13624042631).

The spelling of 11313011320 in words is "eleven billion, three hundred thirteen million, eleven thousand, three hundred twenty".