1131302147 has 2 divisors, whose sum is σ = 1131302148. Its totient is φ = 1131302146.

The previous prime is 1131302087. The next prime is 1131302149. The reversal of 1131302147 is 7412031311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1131302147 - 2⁶ = 1131302083 is a prime.

Together with 1131302149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1131302149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565651073 + 565651074.

It is an arithmetic number, because the mean of its divisors is an integer number (565651074).

Almost surely, 2^1131302147 is an apocalyptic number.

1131302147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131302147 is an equidigital number, since it uses as much as digits as its factorization.

1131302147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

The square root of 1131302147 is about 33634.8353199477. The cubic root of 1131302147 is about 1041.9803695203.

Adding to 1131302147 its reverse (7412031311), we get a palindrome (8543333458).

The spelling of 1131302147 in words is "one billion, one hundred thirty-one million, three hundred two thousand, one hundred forty-seven".