Base | Representation |
---|---|
bin | 10000011101100111010… |
… | …101111110011110001000 |
3 | 11000011002221202101110021 |
4 | 100131213111332132020 |
5 | 122013410403304000 |
6 | 2223414452030224 |
7 | 144506631101242 |
oct | 20354725763610 |
9 | 4004087671407 |
10 | 1131310213000 |
11 | 3a6871138490 |
12 | 163309602374 |
13 | 828b3742b26 |
14 | 3ca81931092 |
15 | 1e66463611a |
hex | 1076757e788 |
1131310213000 has 128 divisors (see below), whose sum is σ = 2987510947200. Its totient is φ = 397199712000.
The previous prime is 1131310212973. The next prime is 1131310213027. The reversal of 1131310213000 is 3120131311.
It is an interprime number because it is at equal distance from previous prime (1131310212973) and next prime (1131310213027).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1454214 + ... + 2092213.
It is an arithmetic number, because the mean of its divisors is an integer number (23339929275).
Almost surely, 21131310213000 is an apocalyptic number.
1131310213000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1131310213000 is an abundant number, since it is smaller than the sum of its proper divisors (1856200734200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131310213000 is a wasteful number, since it uses less digits than its factorization.
1131310213000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3546488 (or 3546474 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1131310213000 its reverse (3120131311), we get a palindrome (1134430344311).
The spelling of 1131310213000 in words is "one trillion, one hundred thirty-one billion, three hundred ten million, two hundred thirteen thousand".
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