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1131313030231 is a prime number
BaseRepresentation
bin10000011101100111100…
…000101110010001010111
311000011010011001111222011
4100131213200232101113
5122013412113431411
62223415032245051
7144506664043606
oct20354740562127
94004104044864
101131313030231
113a687279207a
1216330a540787
13828b41bb227
143ca82065a3d
151e6649e0c21
hex1076782e457

1131313030231 has 2 divisors, whose sum is σ = 1131313030232. Its totient is φ = 1131313030230.

The previous prime is 1131313030201. The next prime is 1131313030261. The reversal of 1131313030231 is 1320303131311.

It is a balanced prime because it is at equal distance from previous prime (1131313030201) and next prime (1131313030261).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131313030231 is a prime.

It is a super-2 number, since 2×11313130302312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131313030201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565656515115 + 565656515116.

It is an arithmetic number, because the mean of its divisors is an integer number (565656515116).

Almost surely, 21131313030231 is an apocalyptic number.

1131313030231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131313030231 is an equidigital number, since it uses as much as digits as its factorization.

1131313030231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 1131313030231 its reverse (1320303131311), we get a palindrome (2451616161542).

The spelling of 1131313030231 in words is "one trillion, one hundred thirty-one billion, three hundred thirteen million, thirty thousand, two hundred thirty-one".