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11313131310 = 2325139669343
BaseRepresentation
bin10101000100101000…
…01010111100101110
31002012102122121122100
422202110022330232
5141132130200220
65110331355530
7550231013055
oct124224127456
932172577570
1011313131310
114885a70aa8
1222388b2ba6
1310b3a72350
1479470139c
154632e3d90
hex2a250af2e

11313131310 has 48 divisors (see below), whose sum is σ = 31676770944. Its totient is φ = 2784770496.

The previous prime is 11313131303. The next prime is 11313131317. The reversal of 11313131310 is 1313131311.

11313131310 is a `hidden beast` number, since 11 + 31 + 313 + 1 + 310 = 666.

It is an interprime number because it is at equal distance from previous prime (11313131303) and next prime (11313131317).

It is a super-2 number, since 2×113131313102 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313131317) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4833502 + ... + 4835841.

It is an arithmetic number, because the mean of its divisors is an integer number (659932728).

Almost surely, 211313131310 is an apocalyptic number.

11313131310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11313131310 is an abundant number, since it is smaller than the sum of its proper divisors (20363639634).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313131310 is a wasteful number, since it uses less digits than its factorization.

11313131310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9669369 (or 9669366 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 11313131310 its reverse (1313131311), we get a palindrome (12626262621).

Subtracting from 11313131310 its reverse (1313131311), we obtain a palindrome (9999999999).

It can be divided in two parts, 113131 and 31310, that added together give a palindrome (144441).

The spelling of 11313131310 in words is "eleven billion, three hundred thirteen million, one hundred thirty-one thousand, three hundred ten".

Divisors: 1 2 3 5 6 9 10 13 15 18 26 30 39 45 65 78 90 117 130 195 234 390 585 1170 9669343 19338686 29008029 48346715 58016058 87024087 96693430 125701459 145040145 174048174 251402918 290080290 377104377 435120435 628507295 754208754 870240870 1131313131 1257014590 1885521885 2262626262 3771043770 5656565655 11313131310