Base | Representation |
---|---|
bin | 1010010010100000111101… |
… | …0001111100110001110100 |
3 | 1111001112100101010102111201 |
4 | 2210220033101330301310 |
5 | 2440323413224040200 |
6 | 40021113515142244 |
7 | 2245231435142125 |
oct | 244501721746164 |
9 | 44045311112451 |
10 | 11313200221300 |
11 | 36719a065490a |
12 | 13286a7a44984 |
13 | 640aa3c585a3 |
14 | 2b17c188204c |
15 | 149437b69c6a |
hex | a4a0f47cc74 |
11313200221300 has 36 divisors (see below), whose sum is σ = 24696648375840. Its totient is φ = 4498182596320.
The previous prime is 11313200221273. The next prime is 11313200221307. The reversal of 11313200221300 is 312200231311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313200221307) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 338701870 + ... + 338735269.
It is an arithmetic number, because the mean of its divisors is an integer number (686018010440).
Almost surely, 211313200221300 is an apocalyptic number.
11313200221300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11313200221300 is an abundant number, since it is smaller than the sum of its proper divisors (13383448154540).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313200221300 is a wasteful number, since it uses less digits than its factorization.
11313200221300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 677437320 (or 677437313 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 11313200221300 its reverse (312200231311), we get a palindrome (11625400452611).
The spelling of 11313200221300 in words is "eleven trillion, three hundred thirteen billion, two hundred million, two hundred twenty-one thousand, three hundred".
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