Base | Representation |
---|---|
bin | 10101000100101000… |
… | …11111001111100010 |
3 | 1002012102210211200000 |
4 | 22202110133033202 |
5 | 141132140330214 |
6 | 5110333240430 |
7 | 550231510314 |
oct | 124224371742 |
9 | 32172724600 |
10 | 11313214434 |
11 | 48860184a5 |
12 | 2238933116 |
13 | 10b3aa1132 |
14 | 7947237b4 |
15 | 46330d809 |
hex | 2a251f3e2 |
11313214434 has 96 divisors (see below), whose sum is σ = 27257368320. Its totient is φ = 3504114432.
The previous prime is 11313214421. The next prime is 11313214453. The reversal of 11313214434 is 43441231311.
11313214434 is a `hidden beast` number, since 1 + 1 + 3 + 13 + 214 + 434 = 666.
11313214434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 11313214398 and 11313214407.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 644032 + ... + 661364.
It is an arithmetic number, because the mean of its divisors is an integer number (283930920).
Almost surely, 211313214434 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11313214434, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13628684160).
11313214434 is an abundant number, since it is smaller than the sum of its proper divisors (15944153886).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313214434 is a wasteful number, since it uses less digits than its factorization.
11313214434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17446 (or 17434 counting only the distinct ones).
The product of its digits is 3456, while the sum is 27.
Adding to 11313214434 its reverse (43441231311), we get a palindrome (54754445745).
The spelling of 11313214434 in words is "eleven billion, three hundred thirteen million, two hundred fourteen thousand, four hundred thirty-four".
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