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1131329491 is a prime number
BaseRepresentation
bin100001101101110…
…1011011111010011
32220211210111022021
41003123223133103
54304110020431
6304132152311
740015066465
oct10333533723
92824714267
101131329491
11530673656
12276a68697
131504ccb46
14aa376135
15694c3b11
hex436eb7d3

1131329491 has 2 divisors, whose sum is σ = 1131329492. Its totient is φ = 1131329490.

The previous prime is 1131329489. The next prime is 1131329509. The reversal of 1131329491 is 1949231311.

It is a weak prime.

It is an emirp because it is prime and its reverse (1949231311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131329491 - 21 = 1131329489 is a prime.

Together with 1131329489, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1131329401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565664745 + 565664746.

It is an arithmetic number, because the mean of its divisors is an integer number (565664746).

Almost surely, 21131329491 is an apocalyptic number.

1131329491 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131329491 is an equidigital number, since it uses as much as digits as its factorization.

1131329491 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5832, while the sum is 34.

The square root of 1131329491 is about 33635.2418008255. The cubic root of 1131329491 is about 1041.9887644723.

It can be divided in two parts, 11313 and 29491, that added together give a palindrome (40804).

The spelling of 1131329491 in words is "one billion, one hundred thirty-one million, three hundred twenty-nine thousand, four hundred ninety-one".