Base | Representation |
---|---|
bin | 10000011101101000100… |
… | …001011101100110010111 |
3 | 11000011011022222201220101 |
4 | 100131220201131212113 |
5 | 122013430440020203 |
6 | 2223420440114531 |
7 | 144510261226135 |
oct | 20355041354627 |
9 | 4004138881811 |
10 | 1131330001303 |
11 | 3a6881323757 |
12 | 163314165a47 |
13 | 828b7880a98 |
14 | 3ca84402755 |
15 | 1e66624441d |
hex | 1076885d997 |
1131330001303 has 2 divisors, whose sum is σ = 1131330001304. Its totient is φ = 1131330001302.
The previous prime is 1131330001267. The next prime is 1131330001313. The reversal of 1131330001303 is 3031000331311.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (3031000331311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131330001303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131330001313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565665000651 + 565665000652.
It is an arithmetic number, because the mean of its divisors is an integer number (565665000652).
Almost surely, 21131330001303 is an apocalyptic number.
1131330001303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131330001303 is an equidigital number, since it uses as much as digits as its factorization.
1131330001303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 19.
Adding to 1131330001303 its reverse (3031000331311), we get a palindrome (4162330332614).
The spelling of 1131330001303 in words is "one trillion, one hundred thirty-one billion, three hundred thirty million, one thousand, three hundred three".
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