Base | Representation |
---|---|
bin | 11001101110010011011010… |
… | …111110001001001001011011 |
3 | 112211120102100010002112022221 |
4 | 121232103122332021021123 |
5 | 104312033103222100443 |
6 | 1040340345001524511 |
7 | 32554411662615406 |
oct | 3156233276111133 |
9 | 484512303075287 |
10 | 113133112300123 |
11 | 33058535579163 |
12 | 10831b564a3737 |
13 | 4b18539719696 |
14 | 1dd19597bcd3d |
15 | d12cba142eed |
hex | 66e4daf8925b |
113133112300123 has 2 divisors, whose sum is σ = 113133112300124. Its totient is φ = 113133112300122.
The previous prime is 113133112300073. The next prime is 113133112300147. The reversal of 113133112300123 is 321003211331311.
It is a strong prime.
It is an emirp because it is prime and its reverse (321003211331311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113133112300123 is a prime.
It is not a weakly prime, because it can be changed into another prime (113133112304123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566556150061 + 56566556150062.
It is an arithmetic number, because the mean of its divisors is an integer number (56566556150062).
Almost surely, 2113133112300123 is an apocalyptic number.
113133112300123 is a deficient number, since it is larger than the sum of its proper divisors (1).
113133112300123 is an equidigital number, since it uses as much as digits as its factorization.
113133112300123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 113133112300123 its reverse (321003211331311), we get a palindrome (434136323631434).
The spelling of 113133112300123 in words is "one hundred thirteen trillion, one hundred thirty-three billion, one hundred twelve million, three hundred thousand, one hundred twenty-three".
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