Base | Representation |
---|---|
bin | 10000011101101000101… |
… | …010001111001000010011 |
3 | 11000011011111022120221121 |
4 | 100131220222033020103 |
5 | 122013432032120311 |
6 | 2223421001303111 |
7 | 144510316615561 |
oct | 20355052171023 |
9 | 4004144276847 |
10 | 1131332301331 |
11 | 3a6882654801 |
12 | 163314a94a97 |
13 | 828b81a794b |
14 | 3ca84840a31 |
15 | 1e66654ab71 |
hex | 10768a8f213 |
1131332301331 has 2 divisors, whose sum is σ = 1131332301332. Its totient is φ = 1131332301330.
The previous prime is 1131332301329. The next prime is 1131332301347. The reversal of 1131332301331 is 1331032331311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1131332301331 - 21 = 1131332301329 is a prime.
It is a super-2 number, since 2×11313323013312 (a number of 25 digits) contains 22 as substring.
Together with 1131332301329, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1131332301296 and 1131332301305.
It is not a weakly prime, because it can be changed into another prime (1131332301311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565666150665 + 565666150666.
It is an arithmetic number, because the mean of its divisors is an integer number (565666150666).
Almost surely, 21131332301331 is an apocalyptic number.
1131332301331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131332301331 is an equidigital number, since it uses as much as digits as its factorization.
1131332301331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 1131332301331 its reverse (1331032331311), we get a palindrome (2462364632642).
The spelling of 1131332301331 in words is "one trillion, one hundred thirty-one billion, three hundred thirty-two million, three hundred one thousand, three hundred thirty-one".
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