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11313323120 = 2451123953791
BaseRepresentation
bin10101000100101001…
…11001110001110000
31002012110000100202102
422202110321301300
5141132202314440
65110335435532
7550232442221
oct124224716160
932173010672
1011313323120
114886092120
122238985ba8
1310b3b0b748
14794751248
15463330b15
hex2a2539c70

11313323120 has 80 divisors (see below), whose sum is σ = 28815298560. Its totient is φ = 4096646400.

The previous prime is 11313323113. The next prime is 11313323143. The reversal of 11313323120 is 2132331311.

It is a tau number, because it is divible by the number of its divisors (80).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 11313323092 and 11313323101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 183425 + ... + 237215.

It is an arithmetic number, because the mean of its divisors is an integer number (360191232).

Almost surely, 211313323120 is an apocalyptic number.

11313323120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313323120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14407649280).

11313323120 is an abundant number, since it is smaller than the sum of its proper divisors (17501975440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313323120 is a wasteful number, since it uses less digits than its factorization.

11313323120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54054 (or 54048 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 11313323120 its reverse (2132331311), we get a palindrome (13445654431).

It can be divided in two parts, 11313 and 323120, that added together give a palindrome (334433).

The spelling of 11313323120 in words is "eleven billion, three hundred thirteen million, three hundred twenty-three thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 11 16 20 22 40 44 55 80 88 110 176 220 239 440 478 880 956 1195 1912 2390 2629 3824 4780 5258 9560 10516 13145 19120 21032 26290 42064 52580 53791 105160 107582 210320 215164 268955 430328 537910 591701 860656 1075820 1183402 2151640 2366804 2958505 4303280 4733608 5917010 9467216 11834020 12856049 23668040 25712098 47336080 51424196 64280245 102848392 128560490 141416539 205696784 257120980 282833078 514241960 565666156 707082695 1028483920 1131332312 1414165390 2262664624 2828330780 5656661560 11313323120