Base | Representation |
---|---|
bin | 110100101011101000… |
… | …1101011000101100111 |
3 | 101211000110110012200121 |
4 | 1221113101223011213 |
5 | 3323144122303143 |
6 | 123550041222411 |
7 | 11113360015441 |
oct | 1512721530547 |
9 | 354013405617 |
10 | 113133400423 |
11 | 43a8594523a |
12 | 19b14191a07 |
13 | a88c71a8b4 |
14 | 56933d3491 |
15 | 2e2223c7ed |
hex | 1a5746b167 |
113133400423 has 2 divisors, whose sum is σ = 113133400424. Its totient is φ = 113133400422.
The previous prime is 113133400417. The next prime is 113133400439. The reversal of 113133400423 is 324004331311.
It is a weak prime.
It is an emirp because it is prime and its reverse (324004331311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113133400423 - 229 = 112596529511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113133400463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566700211 + 56566700212.
It is an arithmetic number, because the mean of its divisors is an integer number (56566700212).
Almost surely, 2113133400423 is an apocalyptic number.
113133400423 is a deficient number, since it is larger than the sum of its proper divisors (1).
113133400423 is an equidigital number, since it uses as much as digits as its factorization.
113133400423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 113133400423 its reverse (324004331311), we get a palindrome (437137731734).
The spelling of 113133400423 in words is "one hundred thirteen billion, one hundred thirty-three million, four hundred thousand, four hundred twenty-three".
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