113134125243700 has 36 divisors (see below), whose sum is σ = 267819329215872. Its totient is φ = 41139681906400.

The previous prime is 113134125243683. The next prime is 113134125243707. The reversal of 113134125243700 is 7342521431311.

It is a self number, because there is not a number n which added to its sum of digits gives 113134125243700.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113134125243707) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 51424601284 + ... + 51424603483.

It is an arithmetic number, because the mean of its divisors is an integer number (7439425811552).

Almost surely, 2^{113134125243700} is an apocalyptic number.

113134125243700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113134125243700 is an abundant number, since it is smaller than the sum of its proper divisors (154685203972172).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113134125243700 is a wasteful number, since it uses less digits than its factorization.

113134125243700 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102849204792 (or 102849204785 counting only the distinct ones).

The product of its (nonzero) digits is 60480, while the sum is 37.

The spelling of 113134125243700 in words is "one hundred thirteen trillion, one hundred thirty-four billion, one hundred twenty-five million, two hundred forty-three thousand, seven hundred".