1131401101 has 2 divisors, whose sum is σ = 1131401102. Its totient is φ = 1131401100.

The previous prime is 1131401081. The next prime is 1131401129. The reversal of 1131401101 is 1011041311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1098922500 + 32478601 = 33150^2 + 5699^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131401101 - 2¹⁵ = 1131368333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131401171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565700550 + 565700551.

It is an arithmetic number, because the mean of its divisors is an integer number (565700551).

Almost surely, 2^1131401101 is an apocalyptic number.

It is an amenable number.

1131401101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131401101 is an equidigital number, since it uses as much as digits as its factorization.

1131401101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 1131401101 is about 33636.3062924573. The cubic root of 1131401101 is about 1042.0107490022.

Adding to 1131401101 its reverse (1011041311), we get a palindrome (2142442412).

The spelling of 1131401101 in words is "one billion, one hundred thirty-one million, four hundred one thousand, one hundred one".