Base | Representation |
---|---|
bin | 1010010010100100000011… |
… | …0100110100000000100011 |
3 | 1111001121111022012220200202 |
4 | 2210221000310310000203 |
5 | 2440332114022202003 |
6 | 40021332211135415 |
7 | 2245261150336001 |
oct | 244510064640043 |
9 | 44047438186622 |
10 | 11314031444003 |
11 | 3672287880822 |
12 | 132889a2a456b |
13 | 640ba7220b42 |
14 | 2b1860017a71 |
15 | 149485b0d088 |
hex | a4a40d34023 |
11314031444003 has 2 divisors, whose sum is σ = 11314031444004. Its totient is φ = 11314031444002.
The previous prime is 11314031443973. The next prime is 11314031444057. The reversal of 11314031444003 is 30044413041311.
It is a weak prime.
It is an emirp because it is prime and its reverse (30044413041311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11314031444003 - 214 = 11314031427619 is a prime.
It is not a weakly prime, because it can be changed into another prime (11314031444063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657015722001 + 5657015722002.
It is an arithmetic number, because the mean of its divisors is an integer number (5657015722002).
Almost surely, 211314031444003 is an apocalyptic number.
11314031444003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314031444003 is an equidigital number, since it uses as much as digits as its factorization.
11314031444003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 11314031444003 its reverse (30044413041311), we get a palindrome (41358444485314).
The spelling of 11314031444003 in words is "eleven trillion, three hundred fourteen billion, thirty-one million, four hundred forty-four thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •