11314031444057 has 2 divisors, whose sum is σ = 11314031444058. Its totient is φ = 11314031444056.

The previous prime is 11314031444003. The next prime is 11314031444063. The reversal of 11314031444057 is 75044413041311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11264239538176 + 49791905881 = 3356224^2 + 223141^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314031444057 - 2³² = 11309736476761 is a prime.

It is a super-2 number, since 2×11314031444057² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11314031444057.

It is not a weakly prime, because it can be changed into another prime (11314031444087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657015722028 + 5657015722029.

It is an arithmetic number, because the mean of its divisors is an integer number (5657015722029).

Almost surely, 2^{11314031444057} is an apocalyptic number.

It is an amenable number.

11314031444057 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314031444057 is an equidigital number, since it uses as much as digits as its factorization.

11314031444057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80640, while the sum is 38.

Adding to 11314031444057 its reverse (75044413041311), we get a palindrome (86358444485368).

The spelling of 11314031444057 in words is "eleven trillion, three hundred fourteen billion, thirty-one million, four hundred forty-four thousand, fifty-seven".