Base | Representation |
---|---|
bin | 1010010010100100000011… |
… | …0100110100000000100100 |
3 | 1111001121111022012220200210 |
4 | 2210221000310310000210 |
5 | 2440332114022202004 |
6 | 40021332211135420 |
7 | 2245261150336002 |
oct | 244510064640044 |
9 | 44047438186623 |
10 | 11314031444004 |
11 | 3672287880823 |
12 | 132889a2a4570 |
13 | 640ba7220b43 |
14 | 2b1860017a72 |
15 | 149485b0d089 |
hex | a4a40d34024 |
11314031444004 has 48 divisors (see below), whose sum is σ = 27954686366208. Its totient is φ = 3549198678528.
The previous prime is 11314031444003. The next prime is 11314031444057. The reversal of 11314031444004 is 40044413041311.
It is a super-2 number, since 2×113140314440042 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11314031444003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 59982 + ... + 4757274.
It is an arithmetic number, because the mean of its divisors is an integer number (582389299296).
Almost surely, 211314031444004 is an apocalyptic number.
It is an amenable number.
11314031444004 is an abundant number, since it is smaller than the sum of its proper divisors (16640654922204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11314031444004 is a wasteful number, since it uses less digits than its factorization.
11314031444004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4709124 (or 4709122 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 30.
Adding to 11314031444004 its reverse (40044413041311), we get a palindrome (51358444485315).
The spelling of 11314031444004 in words is "eleven trillion, three hundred fourteen billion, thirty-one million, four hundred forty-four thousand, four".
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