11314100141 has 2 divisors, whose sum is σ = 11314100142. Its totient is φ = 11314100140.

The previous prime is 11314100089. The next prime is 11314100143. The reversal of 11314100141 is 14100141311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10380553225 + 933546916 = 101885^2 + 30554^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11314100141 is a prime.

Together with 11314100143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11314100143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657050070 + 5657050071.

It is an arithmetic number, because the mean of its divisors is an integer number (5657050071).

Almost surely, 2^11314100141 is an apocalyptic number.

It is an amenable number.

11314100141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314100141 is an equidigital number, since it uses as much as digits as its factorization.

11314100141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11314100141 its reverse (14100141311), we get a palindrome (25414241452).

The spelling of 11314100141 in words is "eleven billion, three hundred fourteen million, one hundred thousand, one hundred forty-one".