Base | Representation |
---|---|
bin | 10000011101101101011… |
… | …000001000000101111111 |
3 | 11000011101000020020210101 |
4 | 100131231120020011333 |
5 | 122014112312034444 |
6 | 2223432505421531 |
7 | 144512300363551 |
oct | 20355530100577 |
9 | 4004330206711 |
10 | 1131411439999 |
11 | 3a6913297865 |
12 | 16333749a8a7 |
13 | 828cb6c5c69 |
14 | 3ca911614d1 |
15 | 1e66d47e3d4 |
hex | 1076d60817f |
1131411439999 has 2 divisors, whose sum is σ = 1131411440000. Its totient is φ = 1131411439998.
The previous prime is 1131411439987. The next prime is 1131411440059. The reversal of 1131411439999 is 9999341141311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1131411439999 - 25 = 1131411439967 is a prime.
It is a super-2 number, since 2×11314114399992 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131411439969) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565705719999 + 565705720000.
It is an arithmetic number, because the mean of its divisors is an integer number (565705720000).
Almost surely, 21131411439999 is an apocalyptic number.
1131411439999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131411439999 is an equidigital number, since it uses as much as digits as its factorization.
1131411439999 is an evil number, because the sum of its binary digits is even.
The product of its digits is 944784, while the sum is 55.
The spelling of 1131411439999 in words is "one trillion, one hundred thirty-one billion, four hundred eleven million, four hundred thirty-nine thousand, nine hundred ninety-nine".
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