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11314124117 is a prime number
BaseRepresentation
bin10101000100101111…
…11101010101010101
31002012111112001111222
422202113331111111
5141132403432432
65110404540125
7550242316412
oct124227752525
932174461458
1011314124117
1148865899aa
1222390b1645
1310b402c1ca
147948bd109
1546343d112
hex2a25fd555

11314124117 has 2 divisors, whose sum is σ = 11314124118. Its totient is φ = 11314124116.

The previous prime is 11314124111. The next prime is 11314124141. The reversal of 11314124117 is 71142141311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11313725956 + 398161 = 106366^2 + 631^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314124117 - 28 = 11314123861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11314124111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657062058 + 5657062059.

It is an arithmetic number, because the mean of its divisors is an integer number (5657062059).

Almost surely, 211314124117 is an apocalyptic number.

It is an amenable number.

11314124117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314124117 is an equidigital number, since it uses as much as digits as its factorization.

11314124117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 672, while the sum is 26.

Adding to 11314124117 its reverse (71142141311), we get a palindrome (82456265428).

The spelling of 11314124117 in words is "eleven billion, three hundred fourteen million, one hundred twenty-four thousand, one hundred seventeen".