Base | Representation |
---|---|
bin | 110100101011110111… |
… | …1100101100010010000 |
3 | 101211001000012121022101 |
4 | 1221113233211202100 |
5 | 3323203124221000 |
6 | 123550521250144 |
7 | 11113513455253 |
oct | 1512757454220 |
9 | 354030177271 |
10 | 113141242000 |
11 | 43a8a310786 |
12 | 19b16933954 |
13 | a891234b97 |
14 | 569447509a |
15 | 2e22c8ae6a |
hex | 1a57be5890 |
113141242000 has 80 divisors (see below), whose sum is σ = 273682451952. Its totient is φ = 45238809600.
The previous prime is 113141241979. The next prime is 113141242007. The reversal of 113141242000 is 242141311.
It can be written as a sum of positive squares in 8 ways, for example, as 51581677456 + 61559564544 = 227116^2 + 248112^2 .
It is a tau number, because it is divible by the number of its divisors (80).
It is not an unprimeable number, because it can be changed into a prime (113141242007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5896422 + ... + 5915578.
Almost surely, 2113141242000 is an apocalyptic number.
113141242000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113141242000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (136841225976).
113141242000 is an abundant number, since it is smaller than the sum of its proper divisors (160541209952).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113141242000 is a wasteful number, since it uses less digits than its factorization.
113141242000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22133 (or 22117 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 113141242000 its reverse (242141311), we get a palindrome (113383383311).
The spelling of 113141242000 in words is "one hundred thirteen billion, one hundred forty-one million, two hundred forty-two thousand".
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