Base | Representation |
---|---|
bin | 100001101101111… |
… | …1111101111000101 |
3 | 2220211221201001202 |
4 | 1003123333233011 |
5 | 4304120144141 |
6 | 304134032245 |
7 | 40015563326 |
oct | 10333775705 |
9 | 2824851052 |
10 | 1131412421 |
11 | 53071a997 |
12 | 276aa8685 |
13 | 15052b809 |
14 | aa39844d |
15 | 694dd49b |
hex | 436ffbc5 |
1131412421 has 2 divisors, whose sum is σ = 1131412422. Its totient is φ = 1131412420.
The previous prime is 1131412417. The next prime is 1131412423. The reversal of 1131412421 is 1242141311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 932997025 + 198415396 = 30545^2 + 14086^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131412421 - 22 = 1131412417 is a prime.
Together with 1131412423, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131412393 and 1131412402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131412423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565706210 + 565706211.
It is an arithmetic number, because the mean of its divisors is an integer number (565706211).
Almost surely, 21131412421 is an apocalyptic number.
It is an amenable number.
1131412421 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131412421 is an equidigital number, since it uses as much as digits as its factorization.
1131412421 is an evil number, because the sum of its binary digits is even.
The product of its digits is 192, while the sum is 20.
The square root of 1131412421 is about 33636.4745625935. The cubic root of 1131412421 is about 1042.0142241984.
Adding to 1131412421 its reverse (1242141311), we get a palindrome (2373553732).
The spelling of 1131412421 in words is "one billion, one hundred thirty-one million, four hundred twelve thousand, four hundred twenty-one".
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