Base | Representation |
---|---|
bin | 10101000100110000… |
… | …00001101101100101 |
3 | 1002012111112222010021 |
4 | 22202120001231211 |
5 | 141132410021203 |
6 | 5110405155141 |
7 | 550242422614 |
oct | 124230015545 |
9 | 32174488107 |
10 | 11314142053 |
11 | 48865a1425 |
12 | 22390bbab1 |
13 | 10b4037416 |
14 | 7948c587b |
15 | 4634435bd |
hex | 2a2601b65 |
11314142053 has 2 divisors, whose sum is σ = 11314142054. Its totient is φ = 11314142052.
The previous prime is 11314142033. The next prime is 11314142089. The reversal of 11314142053 is 35024141311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9993401089 + 1320740964 = 99967^2 + 36342^2 .
It is a cyclic number.
It is not a de Polignac number, because 11314142053 - 29 = 11314141541 is a prime.
It is a super-5 number, since 5×113141420535 (a number of 51 digits) contains 55555 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11314142033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657071026 + 5657071027.
It is an arithmetic number, because the mean of its divisors is an integer number (5657071027).
Almost surely, 211314142053 is an apocalyptic number.
It is an amenable number.
11314142053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314142053 is an equidigital number, since it uses as much as digits as its factorization.
11314142053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 11314142053 its reverse (35024141311), we get a palindrome (46338283364).
The spelling of 11314142053 in words is "eleven billion, three hundred fourteen million, one hundred forty-two thousand, fifty-three".
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