Base | Representation |
---|---|
bin | 1010010010100100100000… |
… | …0001100101011001000101 |
3 | 1111001121210201111121101102 |
4 | 2210221020001211121011 |
5 | 2440332340432420032 |
6 | 40021352204105445 |
7 | 2245264145123051 |
oct | 244511001453105 |
9 | 44047721447342 |
10 | 11314152232517 |
11 | 3672339a80a42 |
12 | 1328912835285 |
13 | 640bc6262934 |
14 | 2b187209ac61 |
15 | 14949151c362 |
hex | a4a48065645 |
11314152232517 has 2 divisors, whose sum is σ = 11314152232518. Its totient is φ = 11314152232516.
The previous prime is 11314152232447. The next prime is 11314152232561. The reversal of 11314152232517 is 71523225141311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7871312803396 + 3442839429121 = 2805586^2 + 1855489^2 .
It is a cyclic number.
It is not a de Polignac number, because 11314152232517 - 232 = 11309857265221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11314152232577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657076116258 + 5657076116259.
It is an arithmetic number, because the mean of its divisors is an integer number (5657076116259).
Almost surely, 211314152232517 is an apocalyptic number.
It is an amenable number.
11314152232517 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314152232517 is an equidigital number, since it uses as much as digits as its factorization.
11314152232517 is an evil number, because the sum of its binary digits is even.
The product of its digits is 50400, while the sum is 38.
Adding to 11314152232517 its reverse (71523225141311), we get a palindrome (82837377373828).
The spelling of 11314152232517 in words is "eleven trillion, three hundred fourteen billion, one hundred fifty-two million, two hundred thirty-two thousand, five hundred seventeen".
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