11314300030000 has 100 divisors (see below), whose sum is σ = 29883329529768. Its totient is φ = 4114290880000.

The previous prime is 11314300029961. The next prime is 11314300030001. The reversal of 11314300030000 is 3000341311.

It is a tau number, because it is divible by the number of its divisors (100).

It is a Harshad number since it is a multiple of its sum of digits (16).

It is not an unprimeable number, because it can be changed into a prime (11314300030001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 51318637 + ... + 51538636.

Almost surely, 2^{11314300030000} is an apocalyptic number.

11314300030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11314300030000 is an abundant number, since it is smaller than the sum of its proper divisors (18569029499768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11314300030000 is a wasteful number, since it uses less digits than its factorization.

11314300030000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102857312 (or 102857291 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 11314300030000 its reverse (3000341311), we get a palindrome (11317300371311).

The spelling of 11314300030000 in words is "eleven trillion, three hundred fourteen billion, three hundred million, thirty thousand".