1131430508543 has 4 divisors (see below), whose sum is σ = 1131455534088. Its totient is φ = 1131405483000.

The previous prime is 1131430508531. The next prime is 1131430508573. The reversal of 1131430508543 is 3458050341311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131430508543 - 2⁸ = 1131430508287 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131430508497 and 1131430508506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131430508573) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12444833 + ... + 12535418.

It is an arithmetic number, because the mean of its divisors is an integer number (282863883522).

Almost surely, 2^{1131430508543} is an apocalyptic number.

1131430508543 is a deficient number, since it is larger than the sum of its proper divisors (25025545).

1131430508543 is an equidigital number, since it uses as much as digits as its factorization.

1131430508543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25025544.

The product of its (nonzero) digits is 86400, while the sum is 38.

Adding to 1131430508543 its reverse (3458050341311), we get a palindrome (4589480849854).

The spelling of 1131430508543 in words is "one trillion, one hundred thirty-one billion, four hundred thirty million, five hundred eight thousand, five hundred forty-three".