Base | Representation |
---|---|
bin | 110100101011111011… |
… | …1001000011011011101 |
3 | 101211001010221002112011 |
4 | 1221113313020123131 |
5 | 3323204131014213 |
6 | 123551031511221 |
7 | 11113536333652 |
oct | 1512767103335 |
9 | 354033832464 |
10 | 113143219933 |
11 | 43a90441837 |
12 | 19b17528511 |
13 | a891778263 |
14 | 569482bc29 |
15 | 2e2302c03d |
hex | 1a57dc86dd |
113143219933 has 2 divisors, whose sum is σ = 113143219934. Its totient is φ = 113143219932.
The previous prime is 113143219927. The next prime is 113143220017. The reversal of 113143219933 is 339912341311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112948422084 + 194797849 = 336078^2 + 13957^2 .
It is an emirp because it is prime and its reverse (339912341311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113143219933 - 29 = 113143219421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113143219633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56571609966 + 56571609967.
It is an arithmetic number, because the mean of its divisors is an integer number (56571609967).
Almost surely, 2113143219933 is an apocalyptic number.
It is an amenable number.
113143219933 is a deficient number, since it is larger than the sum of its proper divisors (1).
113143219933 is an equidigital number, since it uses as much as digits as its factorization.
113143219933 is an evil number, because the sum of its binary digits is even.
The product of its digits is 52488, while the sum is 40.
The spelling of 113143219933 in words is "one hundred thirteen billion, one hundred forty-three million, two hundred nineteen thousand, nine hundred thirty-three".
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