Base | Representation |
---|---|
bin | 110100101011111011… |
… | …1001000011100110001 |
3 | 101211001010221002122021 |
4 | 1221113313020130301 |
5 | 3323204131020032 |
6 | 123551031511441 |
7 | 11113536334132 |
oct | 1512767103461 |
9 | 354033832567 |
10 | 113143220017 |
11 | 43a90441903 |
12 | 19b17528581 |
13 | a8917782c9 |
14 | 569482bc89 |
15 | 2e2302c097 |
hex | 1a57dc8731 |
113143220017 has 2 divisors, whose sum is σ = 113143220018. Its totient is φ = 113143220016.
The previous prime is 113143219933. The next prime is 113143220033. The reversal of 113143220017 is 710022341311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 57331992481 + 55811227536 = 239441^2 + 236244^2 .
It is a cyclic number.
It is not a de Polignac number, because 113143220017 - 211 = 113143217969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113143219973 and 113143220000.
It is not a weakly prime, because it can be changed into another prime (113143220117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56571610008 + 56571610009.
It is an arithmetic number, because the mean of its divisors is an integer number (56571610009).
Almost surely, 2113143220017 is an apocalyptic number.
It is an amenable number.
113143220017 is a deficient number, since it is larger than the sum of its proper divisors (1).
113143220017 is an equidigital number, since it uses as much as digits as its factorization.
113143220017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 113143220017 its reverse (710022341311), we get a palindrome (823165561328).
The spelling of 113143220017 in words is "one hundred thirteen billion, one hundred forty-three million, two hundred twenty thousand, seventeen".
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