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113143220017 is a prime number
BaseRepresentation
bin110100101011111011…
…1001000011100110001
3101211001010221002122021
41221113313020130301
53323204131020032
6123551031511441
711113536334132
oct1512767103461
9354033832567
10113143220017
1143a90441903
1219b17528581
13a8917782c9
14569482bc89
152e2302c097
hex1a57dc8731

113143220017 has 2 divisors, whose sum is σ = 113143220018. Its totient is φ = 113143220016.

The previous prime is 113143219933. The next prime is 113143220033. The reversal of 113143220017 is 710022341311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57331992481 + 55811227536 = 239441^2 + 236244^2 .

It is a cyclic number.

It is not a de Polignac number, because 113143220017 - 211 = 113143217969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113143219973 and 113143220000.

It is not a weakly prime, because it can be changed into another prime (113143220117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56571610008 + 56571610009.

It is an arithmetic number, because the mean of its divisors is an integer number (56571610009).

Almost surely, 2113143220017 is an apocalyptic number.

It is an amenable number.

113143220017 is a deficient number, since it is larger than the sum of its proper divisors (1).

113143220017 is an equidigital number, since it uses as much as digits as its factorization.

113143220017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 113143220017 its reverse (710022341311), we get a palindrome (823165561328).

The spelling of 113143220017 in words is "one hundred thirteen billion, one hundred forty-three million, two hundred twenty thousand, seventeen".