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113143332031 is a prime number
BaseRepresentation
bin110100101011111011…
…1100011110010111111
3101211001011010210021221
41221113313203302333
53323204143111111
6123551034134211
711113540311532
oct1512767436277
9354034123257
10113143332031
1143a90508a84
1219b17581367
13a8917b72a2
14569485aa19
152e23050371
hex1a57de3cbf

113143332031 has 2 divisors, whose sum is σ = 113143332032. Its totient is φ = 113143332030.

The previous prime is 113143332019. The next prime is 113143332053. The reversal of 113143332031 is 130233341311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113143332031 - 29 = 113143331519 is a prime.

It is a super-2 number, since 2×1131433320312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113143331987 and 113143332005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113143332011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56571666015 + 56571666016.

It is an arithmetic number, because the mean of its divisors is an integer number (56571666016).

Almost surely, 2113143332031 is an apocalyptic number.

113143332031 is a deficient number, since it is larger than the sum of its proper divisors (1).

113143332031 is an equidigital number, since it uses as much as digits as its factorization.

113143332031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 113143332031 its reverse (130233341311), we get a palindrome (243376673342).

The spelling of 113143332031 in words is "one hundred thirteen billion, one hundred forty-three million, three hundred thirty-two thousand, thirty-one".