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1131434123317 is a prime number
BaseRepresentation
bin10000011101101110101…
…110101010000000110101
311000011102120220200110021
4100131232232222000311
5122014134113421232
62223435035525141
7144512664236641
oct20355656520065
94004376820407
101131434123317
113a6925080103
12163342bb97b1
1382903308844
143ca94187c21
151e670460397
hex1076ebaa035

1131434123317 has 2 divisors, whose sum is σ = 1131434123318. Its totient is φ = 1131434123316.

The previous prime is 1131434123311. The next prime is 1131434123329. The reversal of 1131434123317 is 7133214341311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 903338094481 + 228096028836 = 950441^2 + 477594^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131434123317 is a prime.

It is a super-2 number, since 2×11314341233172 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131434123311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565717061658 + 565717061659.

It is an arithmetic number, because the mean of its divisors is an integer number (565717061659).

Almost surely, 21131434123317 is an apocalyptic number.

It is an amenable number.

1131434123317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131434123317 is an equidigital number, since it uses as much as digits as its factorization.

1131434123317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18144, while the sum is 34.

Adding to 1131434123317 its reverse (7133214341311), we get a palindrome (8264648464628).

The spelling of 1131434123317 in words is "one trillion, one hundred thirty-one billion, four hundred thirty-four million, one hundred twenty-three thousand, three hundred seventeen".