Base | Representation |
---|---|
bin | 1010010010100101011011… |
… | …0100011010111111010111 |
3 | 1111001122110000112212102111 |
4 | 2210221112310122333113 |
5 | 2440333343003042104 |
6 | 40021432552051451 |
7 | 2245303250631616 |
oct | 244512664327727 |
9 | 44048400485374 |
10 | 11314400440279 |
11 | 36724570a0122 |
12 | 1328981993b87 |
13 | 640c357c8631 |
14 | 2b189702b87d |
15 | 1494a81ea404 |
hex | a4a56d1afd7 |
11314400440279 has 2 divisors, whose sum is σ = 11314400440280. Its totient is φ = 11314400440278.
The previous prime is 11314400440201. The next prime is 11314400440319. The reversal of 11314400440279 is 97204400441311.
It is an a-pointer prime, because the next prime (11314400440319) can be obtained adding 11314400440279 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11314400440279 - 227 = 11314266222551 is a prime.
It is a super-3 number, since 3×113144004402793 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11314400444279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657200220139 + 5657200220140.
It is an arithmetic number, because the mean of its divisors is an integer number (5657200220140).
Almost surely, 211314400440279 is an apocalyptic number.
11314400440279 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314400440279 is an equidigital number, since it uses as much as digits as its factorization.
11314400440279 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 40.
The spelling of 11314400440279 in words is "eleven trillion, three hundred fourteen billion, four hundred million, four hundred forty thousand, two hundred seventy-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •